Sabtu, 23 April 2011

tugas 2 (NOT)

#include <iostream.h>
#include <conio.h>
#include <stdio.h>

main()
{
char nama[15], kelas[20], nim[10];
float A, B, C, K, L, M, D, E, F, G, H;
clrscr();
cout<<"\tBIODATA SAYA\n";
cout<<"NIM        :"    ;cin>>nim;
cout<<"Nama        :"    ;gets(nama);
cout<<"Kelas        :"    ;cin>>kelas;
cout<<endl;
cout<<"(^o^)/-----------------------(^o^)/"<<endl;
cout<<endl;
cout<<"\tNilai A =";cin>>A;
cout<<"\tNilai B =";cin>>B;
cout<<"\tNilai C =";cin>>C;
cout<<"\tNilai K =";cin>>K;
cout<<"\tNilai L =";cin>>L;
cout<<"\tNilai M =";cin>>M;
cout<<endl;
cout<<"(^o^)/-----------------------(^o^)/"<<endl;
//proses
D = !(4+2>A&&B-2>3+2||B+2<=6+2);
E = !(K+5<M||M<L&&2*M-L>0);
F = !(L+5<M||C*K<L&&2*K-L>0);
G = !(A*4<=3*M+B);
H = !(K+10>A&&L-2>4*C);

cout<<endl;
cout<<"\tprogram ekspresi NOT"<<endl<<endl;
cout<<"hasil dari D = (4+2>A&&B-2>3+2||B+2<=6+2) adalah" <<D<<endl;
cout<<"hasil dari E = K+5<M||M<L&&2*M-L>0 adalah" <<E<<endl;
cout<<"hasil dari F = L+5<M||C*K<L&&2*K-L>0 adalah" <<F<<endl;
cout<<"hasil dari G = A*4<=3*M+B adalah" <<G<<endl;
cout<<"hasil dari H = K+10>A&&L-2>4*C adalah" <<H<<endl;
cout<<endl<<endl;
cout<<"(^o^)/-----------------------(^o^)/"<<endl;
cout<<endl;
getch();
}
sudah berhasil di run,kalau mau soal dia atas silahkan download disini

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